How to open the keymap settings page and automatically select an action programmingly?

Question

Already can open the IDE's keymap page by using the code below:

ShowSettingsUtil.getInstance().showSettingsDialog(e.getProject(), KeymapPanel.class);

If want to select an action(e.g., a plugin's action) automatically, is there any good way?

Answer

Try this code. Remember to change IdeActions.ACTION_EXPAND_LIVE_TEMPLATE_CUSTOM to your action ID:

// Some Action Class
public void actionPerformed(AnActionEvent e) {
        Settings allSettings = Settings.KEY.getData(e.getDataContext());
        final KeymapPanel keymapPanel = allSettings == null ? new KeymapPanel() : allSettings.find(KeymapPanel.class);
        if (keymapPanel == null) return;

        Runnable selectAction = () -> keymapPanel.selectAction(IdeActions.ACTION_EXPAND_LIVE_TEMPLATE_CUSTOM);
        if (allSettings != null) {
            allSettings.select(keymapPanel).doWhenDone(selectAction);
        }
        else {
            ShowSettingsUtil.getInstance().editConfigurable(e.getProject(), keymapPanel, selectAction);
        }
}

If you are trying to trigger this action in another Settings page component which is already displayed, change the way to get DataContext:

Settings allSettings = Settings.KEY.getData(DataManager.getInstance().getDataContext(somePreferencesJComponent));

The final effect: